A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is (g = 10 m/s2) nearly :
- 1.4 kg m/s
- 0 kg m/s
- 4.2 kg m/s
- 2.1 kg m/s
Answer
(3) 4.2 kg m/s
Solution
Speed just before striking the ground:
v = 2gh = 2 10 10 = 10 2 m/s
Since it rises to the same height, it rebounds with the same speed v upwards.
Impulse = p = mv - (-mv) = 2mv
= 2 0.15 10 2
= 3 2 4.2 kg m/s
Answer: (3)