Let x and y be real numbers such that 50 ( 2x1+3i- y1-2i )=31+17i, i= -1. Then the value of 10(x-3y) is :
- 20
- 31
- 35
- 75
Answer
(4) 75
Solution
2x1+3i= 2x(1-3i)1+9= x(1-3i)5 and y1-2i= y(1+2i)1+4= y(1+2i)5
∴ 50 ( 2x1+3i- y1-2i )=10 [(x-y)-i(3x+2y) ]=31+17i
Comparing real and imaginary parts (x, y real):
10(x-y)=31 x-y=3.1 …(i)
-10(3x+2y)=17 3x+2y=-1.7 …(ii)
From (i), x=y+3.1; in (ii): 5y+9.3=-1.7 y=-2.2, x=0.9
10(x-3y)=10(0.9+6.6)=75
Answer: (4)