Let , be the roots of the equation x2-3x+r=0, and 2, 2 be the roots of the equation x2+3x+r=0. If the roots of the equation x2+6x=m are 2 + +2r and -2 - r2, then m is equal to :
- -135
- -567
- 135
- 567
Answer
(4) 567
Solution
For x2-3x+r=0: + =3 and =r.
For x2+3x+r=0: 2+2 =-3 and 2 2 = =r (consistent).
+4 =-6
Subtracting + =3: 3 =-9
=-3, =6, r= =-18
Roots of x2+6x-m=0 are
2 + +2r=12-3-36=-27 and -2 - r2=6+6+9=21
Check: sum =-27+21=-6, as required
Product =-m=(-27)(21)=-567
m=567
Answer: (4)