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Complex Numbers and Quadratic Equations · Question 14

JEE Main 2026 (Online) 2nd April Evening ShiftMCQMedium📈 Topic in 26% papers+4−1
1

Let , be the roots of the equation x2-3x+r=0, and 2, 2 be the roots of the equation x2+3x+r=0. If the roots of the equation x2+6x=m are 2 + +2r and -2 - r2, then m is equal to :

  1. -135
  2. -567
  3. 135
  4. 567

Answer

(4) 567

Solution

For x2-3x+r=0: + =3 and =r.

For x2+3x+r=0: 2+2 =-3 and 2 2 = =r (consistent).

+4 =-6

Subtracting + =3: 3 =-9

=-3, =6, r= =-18

Roots of x2+6x-m=0 are

2 + +2r=12-3-36=-27 and -2 - r2=6+6+9=21

Check: sum =-27+21=-6, as required

Product =-m=(-27)(21)=-567

m=567

Answer: (4)

JEE Main 2026 (Online) 2nd April Evening Shift

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2

Let the circles C1 : |z|=r and C2 : |z-3-4i|=5, z C, be such that C2 lies within C1. If z1 moves on C1, z2 moves on C2 and |z1-z2|=2, then |z1-z2| is equal to :

  1. 12
  2. 17
  3. 22
  4. 24
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3

If α, β, where α < β, are the roots of the equation x2 - ( + 3)x + 3 = 0 such that 1 - 1 = 13, then the sum of all possible values of λ is

  1. 2
  2. 6
  3. 8
  4. 4
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4

Let S = \x3 + ax2 + bx + c : a, b, c N and a, b, c 20\ be a set of polynomials. Then the number of polynomials in S, which are divisible by x2 + 2, is

  1. 6
  2. 120
  3. 20
  4. 10
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5

Let z be a complex number such that |z − 6| = 5 and |z + 2 − 6i| = 5. Then the value of z3 + 3z2 - 15z + 141 is equal to :

  1. 61
  2. 37
  3. 42
  4. 50
JEE Main 2026 (Online) 28th January Morning Shift
6

Let the arithmetic mean of 1a and 1b be 516, a > 2. If is such that a, 4, , b are in A.P., then the equation x2 - ax + 2( - 2b) = 0 has :

  1. one root in (1, 4) and another in (-2, 0)
  2. one root in (0, 2) and another in (-4, -2)
  3. both roots in the interval (-2, 0)
  4. complex roots of magnitude less than 2
JEE Main 2026 (Online) 28th January Evening Shift
7

Let A = \z C : |z - 2| 4\ and B = \z C : |z - 2| + |z + 2| = 5\. Then the \|z1 - z2| : z1 A and z2 B\ is :

  1. 172
  2. 8
  3. 9
  4. 152
JEE Main 2026 (Online) 28th January Evening Shift
8

The number of the real solutions of the equation: x|x + 3| + |x - 1| - 2 = 0 is

  1. 3
  2. 2
  3. 5
  4. 4
JEE Main 2026 (Online) 24th January Morning Shift
9

Let S = \z C : | z-6iz-2i | = 1 and | z-8+2iz+2i | = 35 \. Then z S |z|2 is equal to :

  1. 413
  2. 398
  3. 385
  4. 423
JEE Main 2026 (Online) 24th January Morning Shift
10

The smallest positive integral value of a, for which all the roots of x4 - ax2 + 9 = 0 are real and distinct, is equal to

  1. 7
  2. 3
  3. 4
  4. 9
JEE Main 2026 (Online) 24th January Evening Shift
11

Let z = (1 + i)(1 + 2i)(1 + 3i) (1 + ni), where i = -1. If |z|2 = 44200, then n is equal to .

JEE Main 2026 (Online) 24th January Evening Shift

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