If α, β, where α < β, are the roots of the equation x2 - ( + 3)x + 3 = 0 such that 1 - 1 = 13, then the sum of all possible values of λ is
- 2
- 6
- 8
- 4
Answer
(2) 6
Solution
x2 - x - 3x + 3 = 0
( x - 3)(x - 1) = 0
roots are 1 and 3
Case 1: α = 1, β = 3 (needs 3 > 1)
1 - 3 = 13 = 2 (β = 1.5 > 1 ✓)
Case 2: α = 3 , β = 1 (needs 3 < 1)
3 - 1 = 13 = 4 (α = 0.75 < 1 ✓)
sum of all possible values of λ = 2 + 4 = 6
Answer: (2)