A capacitor of capacitance C and potential V has energy E. It is connected to another capacitor of capacitance 2C and potential 2V. Then the loss of energy is x3E, where x is .
Answer
2
Solution
Energy loss on connecting like plates:
U= 12 C1C2C1+C2 (V1-V2 )2
= 12 C 2C3C (2V-V )2= 13CV2
E= 12CV2 CV2=2E
U= 23E x=2
Answer: 2