At a certain temperature, T(K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then change in internal energy of the system is :
- 700 J
- 400 J
- 300 J
- 500 J
Answer
(3) 300 J
Solution
First law of thermodynamics: U = q + w
Heat absorbed by the system ⇒ q = +500 J
Work done by the system ⇒ w = −200 J
⇒ U = 500 + (−200) = 300 J
Answer: (3)