A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 m s-1. It collides with a horizontal spring of force constant 200 N m-1. The maximum compression produced in the spring will be
- 0.5 m
- 0.6 m
- 0.7 m
- 0.2 m
Answer
(2) 0.6 m
Solution
KE of a rolling solid cylinder = 12mv2 + 12I 2 = 12mv2 + 12 ( 12mr2 ) v2r2 = 34mv2
= 34 3 42 = 36 J
At maximum compression, all this energy is stored in the spring:
12kx2 = 36 x2 = 72200 = 0.36
x = 0.6 m
Answer: (2)