A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity . Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by
- (M+2m) 2m
- 2M M+2m
- (M+2m) M
- M M+2m
Answer
(4) M M+2m
Solution
No external torque acts about the axis, so angular momentum is conserved: I1 = I2 '
Initially I1 = Mr2; after attaching the two masses at distance r from the axis, I2 = Mr2 + 2mr2 = (M+2m)r2
Mr2 = (M+2m)r2 '
' = M M+2m
Answer: (4)