The instantaneous angular position of a point on a rotating wheel is given by the equation (t) = 2t3 - 6t2 The torque on the wheel becomes zero at
- t = 1 s
- t = 0.5 s
- t = 0.25 s
- t = 2 s
Answer
(1) t = 1 s
Solution
= d dt = 6t2 - 12t
= d dt = 12t - 12
= I = 0 = 0
12t - 12 = 0 t = 1 s
Answer: (1)