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Structure of Atom · Question 2

JEE Advanced 2026 Paper 2NumericalMedium📈 Topic in 17% papers+4
1

Xa+ and Yb+ are hydrogen-like species. The wavelength of light absorbed during the transition between the states with principal quantum numbers n=1 and n=2 of Xa+ is . The wavelength of light absorbed during the transition between the states with principal quantum numbers n=2 and n=4 of Yb+ is 9 . The lowest possible value of (a+b) is .

Answer

3

Solution

1 =RHZ2 ( 1n12- 1n22 )

X: 1 =RHZX2 34; Y: 19 =RHZY2 ( 14- 116 )=RHZY2 316

Dividing: 9= 4ZX2ZY2 ZXZY= 32

Smallest integers: ZX=3 ( Li2+, a=2), ZY=2 ( He+, b=1)

a+b=3

Answer: 3

JEE Advanced 2026 Paper 2

Keep practising — Structure of Atom

2

Among the following, the correct statement(s) for electrons in an atom is(are)

  1. Uncertainty principle rules out the existence of definite paths for electrons.
  2. The energy of an electron in 2s orbital of an atom is lower than the energy of an electron that is infinitely far away from the nucleus.
  3. According to Bohr’s model, the most negative energy value for an electron is given by n = 1, which corresponds to the most stable orbit.
  4. According to Bohr’s model, the magnitude of velocity of electrons increases with increase in values of n.
JEE Advanced 2024 Paper 1
3

According to Bohr’s model, the highest kinetic energy is associated with the electron in the

  1. first orbit of H atom
  2. first orbit of He+
  3. second orbit of He+
  4. second orbit of Li2+
JEE Advanced 2024 Paper 2

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