According to Bohr’s model, the highest kinetic energy is associated with the electron in the
- first orbit of H atom
- first orbit of He+
- second orbit of He+
- second orbit of Li2+
Answer
(2) first orbit of He+
Solution
In Bohr’s model, KE = -En = 13.6 Z2n2 eV
H, n = 1: 13.6 11 = 13.6 eV
He+, n = 1: 13.6 41 = 54.4 eV
He+, n = 2: 13.6 44 = 13.6 eV
Li2+, n = 2: 13.6 94 = 30.6 eV
Highest KE: first orbit of He+.
Answer: (B)