In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 k is 2 V. If the base resistance is 1 k and the current amplification of the transistor is 100, the input signal voltage is
- 0.1 V
- 1.0 V
- 1 mV
- 10 mV
Answer
(4) 10 mV
Solution
Collector current: IC = V0RC = 22 103 = 10-3 A
Base current: IB = IC = 10-3100 = 10-5 A
Input voltage: Vi = IB RB = 10-5 103
= 10-2 V = 10 mV
Answer: (4)