A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by
- 68%
- 41%
- 200%
- 100%
Answer
(2) 41%
Solution
Speed on reaching the ground: v = 2gh P = m 2gh h
New height h' = h + 100\% of h = 2h
P' = 2 P = 1.414 P
percentage change = P' - PP 100 = (1.414 - 1) 100 41\%
Answer: (2)