The distance travelled by a particle starting from rest and moving with an acceleration 43 m s-2, in the third second is
- 103 m
- 193 m
- 6 m
- 4 m
Answer
(1) 103 m
Solution
Distance travelled in the nth second, sn = u + a2(2n - 1)
Here u = 0, a = 43 m s-2, n = 3
s3 = 0 + 43 2(2 3 - 1)
s3 = 23 5 = 103 m
Answer: (1)