A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then
- S2 = 3S1
- S2 = 4S1
- S2 = S1
- S2 = 2S1
Answer
(2) S2 = 4S1
Solution
Constant force constant acceleration a; u = 0
S = 12at2 S t2
S2S1 = ( 2010 )2 = 4 S2 = 4S1
Answer: (2)