A particle moves a distance x in time t according to equation x = (t + 5)-1. The acceleration of particle is proportional to
- (velocity)3/2
- (distance)2
- (distance)-2
- (velocity)2/3
Answer
(1) (velocity)3/2
Solution
x = (t+5)-1
v = dxdt = -(t+5)-2
a = dvdt = 2(t+5)-3
|v| = (t+5)-2 (t+5)-3 = |v|3/2
a = 2|v|3/2 a (velocity)3/2
Answer: (1)