A massless spring gets elongated by amount x1 under a tension of 5 N. Its elongation is x2 under the tension of 7 N. For the elongation of (5x1-2x2), the tension in the spring will be,
- 20 N
- 39 N
- 11 N
- 15 N
Answer
(3) 11 N
Solution
Hooke's law T=kx: tension is proportional to elongation, so the same combination holds for the tensions.
[figure]
T=5(5)-2(7)=25-14=11 N
Answer: (3)