The two wires A and B of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire A and wire B is 20/11. When the joined wire is kept under certain tension the elongations in the wires A and B are equal. If the length of wire A is 2.2 m, then the length of wire B is m.
- 1.1
- 2.22
- 1.21
- 4.44
Answer
(3) 1.21
Solution
Both wires carry the same tension F and have the same area A:
L= FLAY
LA= LB ⇒ LAYA= LBYB
⇒ LB=LA YBYA=2.2 1120=1.21 m
Answer: (3)