Figure represents the extension ( l) of a wire of length 1 meter, suspended from the ceiling of the room at one end with a load W connected to the other end. If the cross-sectional area of the wire is 10-5 m2 then the Young's modulus of the wire is N/m2. [figure]
- 1.0 1011
- 2.0 1010
- 1.0 1010
- 2.0 1011
Answer
(3) 1.0 1010
Solution
From the graph (straight line through the origin): W=70 N gives l=7 10-4 m
⇒ W l= 707 10-4=105 N/m
Y= stressstrain= W/A l/L= W l LA
Y=105 110-5
∴ Y=1.0 1010 N/m2
Answer: (3)