A square loop of edge length 2 m carrying current of 2 A is placed with its edges parallel to the x-y axis. A magnetic field is passing through the x-y plane and expressed as B = B0(1 + 4x) k, where B0 = 5 T. The net magnetic force experienced by the loop is N.
Answer
160
Solution
[figure]
Forces on the two edges parallel to the x-axis are equal and opposite (same B at matching points), so they cancel.
On the edges parallel to the y-axis, F = ILB, in opposite directions, so
Fnet = IL[B(x1 + 2) - B(x1)] = IL 4B0 2
= 2 2 4 5 2 = 160 N
Answer: 160