A box of mass 5 kg is pulled by a cord, up along a frictionless plane inclined at 30 with the horizontal. The tension in the cord is 30 N. The acceleration of the box is (Take g = 10 m s-2)
- 2 m s-2
- Zero
- 0.1 m s-2
- 1 m s-2
Answer
(4) 1 m s-2
Solution
Along the incline (up the plane positive):
T - mg 30 = ma
30 - 5 10 12 = 5a
5a = 5
a = 1 m s-2
Answer: (4)