A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50 . The gas is now heated to double its temperature. The modified pressure is Pa.
Answer
3730 or 6460
Solution
Closed cylinder volume constant P T (T in kelvin)
P1 = 3230 Pa, T1 = 50 + 273 = 323 K
Case 1: temperature doubled on the Celsius scale: T2 = 100 = 373 K
P2 = 3230 373323 = 3730 Pa
Case 2: absolute temperature doubled: T2 = 646 K
P2 = 3230 2 = 6460 Pa
Both values are accepted.
Answer: 3730 or 6460