Consider the junction diode as ideal. The value of current flowing through AB is [figure]
- 10-1 A
- 10-3 A
- 0 A
- 10-2 A
Answer
(4) 10-2 A
Solution
The p-side (A, at +4 V) is at a higher potential than the n-side (towards B, at -6 V), so the diode is forward biased.
An ideal diode in forward bias has zero resistance.
I = VA - VBR = 4 - (-6)1 103
= 10-2 A
Answer: (4)