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Semiconductor Electronics · Question 45

AIPMT 2015 (Cancelled)MCQEasy📈 Topic in 75% papers+4−1
1

Which logic gate is represented by the following combination of logic gates? [figure]

  1. AND
  2. NOR
  3. OR
  4. NAND

Answer

(1) AND

Solution

Outputs of the NOT gates: Y1 = A, Y2 = B

The last gate is a NOR gate: Y = Y1 + Y2 = A + B

By De Morgan's theorem: A + B = A B = A B

The combination works as an AND gate.

Answer: (1)

AIPMT 2015 (Cancelled)

Keep practising — Semiconductor Electronics

2

If in a p-n junction, a square input signal of 10 V is applied, as shown, [figure] then the output across RL will be

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2015 (Cancelled)
3

The given graph represents V-I characteristic for a semiconductor device. [figure] Which of the following statement is correct ?

  1. It is V-I characteristic for solar cell where, point A represents open circuit voltage and point B short circuit current.
  2. It is for a solar cell and points A and B represent open circuit voltage and current, respectively.
  3. It is for a photodiode and points A and B represent open circuit voltage and current, respectively.
  4. It is for a LED and points A and B represent open circuit voltage and short circuit current, respectively.
AIPMT 2014
4

The barrier potential of a p-n junction depends on Which one of the following is correct ?

  1. A and B only
  2. B only
  3. B and C only
  4. A, B and C
AIPMT 2014
5

In a n-type semiconductor, which of the following statements is true?

  1. Holes are minority carriers and pentavalent atoms are dopants.
  2. Holes are majority carriers and trivalent atoms are dopants.
  3. Electrons are majority carriers and trivalent atoms are dopants.
  4. Electrons are minority carriers and pentavalent atoms are dopants.
NEET 2013
6

The output (X) of the logic circuit shown in figure will be [figure]

  1. X = A . B
  2. X = A + B
  3. X = A . B
  4. X = A . B
NEET 2013
7

In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be

  1. 13G
  2. 54G
  3. 23G
  4. 1.5G
Out of syllabusNEET 2013
8

The output from a NAND gate is divided into two in parallel and fed to another NAND gate. The resulting gate is a [figure]

  1. AND gate
  2. NOR gate
  3. OR gate
  4. NOT gate
NEET 2013 (Karnataka)
9

In an unbiased p-n junction, holes diffuse from the p-region to n-region because of

  1. The attraction of free electrons of n-region.
  2. The higher hole concentration in p-region than that in n-region.
  3. The higher concentration of electrons in the n-region than that in the p-region.
  4. The potential difference across the p-n junction.
NEET 2013 (Karnataka)
10

One way in which the operation of an n-p-n transistor differs from that of a p-n-p is

  1. The emitter junction injects minority carriers into the base region of the p-n-p
  2. The emitter injects holes into the base of the p-n-p and electrons into the base region of n-p-n
  3. The emitter injects holes into the base of n-p-n
  4. The emitter junction is reverse biased in n-p-n
Out of syllabusNEET 2013 (Karnataka)
11

To get an output Y = 1 in given circuit which of the following input will be correct ? [figure]

  1. A 1, B 0, C 0
  2. A 1, B 0, C 1
  3. A 1, B 1, C 0
  4. A 0, B 1, C 0
AIPMT 2012 (Mains)

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