A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 , the voltage gain and the power gain of the amplifier will respectively be
- 4, 4
- 4, 3.69
- 4, 3.84
- 3.69, 3.84
Answer
(3) 4, 3.84
Solution
Current amplification factor = 0.96, RL = 800 , Ri = 192
Voltage gain AV = 0.96 RLRi
= 0.96 800192 = 4
Power gain = 0.96 AV
= 0.96 4 = 3.84
Answer: (3)