Consider an n-type semiconductor in which ne and nh are number of electrons and holes, respectively. Choose the correct answer from the options given below :
- (A), (B), (E) only
- (A), (C), (E) only
- (A), (B), (C) only
- (A), (C), (D) only
Answer
(1) (A), (B), (E) only
Solution
(A) In an n-type semiconductor electrons are the majority carriers and holes are the minority carriers. Correct.
(B) n-type doping is done with a pentavalent (group 15) atom such as P, As or Sb. Correct.
(C) and (D) As per NCERT, in thermal equilibrium ne nh = ni2 for any (intrinsic or extrinsic) semiconductor. So ne nh ni2 is wrong, and ne nh is never greater than ni2. Both incorrect.
(E) A donor atom gives only a free electron (and becomes a fixed positive ion); the few holes come from thermal generation of electron–hole pairs, not from the donors. Correct.
(A), (B), (E) only
Answer: (1)