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Chemical Kinetics

JEE Main 2025 (Online) 23rd January Evening ShiftMCQEasy📈 Topic in 11% papers+4−1
Ques. 1JEE Main 2025, 23 January (Evening Shift)

Which of the following graphs most appropriately represents a zero order reaction?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(2) [figure]

Solution

Zero order: rate = k ⇒ [A]t=[A]0-kt, a falling straight line:

[figure]

Answer: (2)

Keep practising — Chemical Kinetics

Ques. 2JEE Main 2025, 22 January (Morning Shift)

A B The molecule A changes into its isomeric form B by following a first order kinetics at a temperature of 1000 K. If the energy barrier with respect to reactant energy for such isomeric transformation is 191.48 kJ mol-1 and the frequency factor is 1020, the time required for 50\% molecules of A to become B is picoseconds (nearest integer). [R=8.314 J K-1 mol-1 ]

Ques. 3JEE Main 2025, 22 January (Morning Shift)

Which of the following statement is not true for radioactive decay?

  1. Half life is 2 times of 1rate constant.
  2. Decay constant increases with increase in temperature.
  3. Decay constant does not depend upon temperature.
  4. Amount of radioactive substance remained after three half lives is 18th of original amount.
Out of syllabus
Ques. 4JEE Main 2025, 22 January (Evening Shift)

Consider the given figure and choose the correct option : [figure]

  1. Activation energy of both forward and backward reaction is E1 + E2 and reactant is more stable than product.
  2. Activation energy of forward reaction is E1 + E2 and product is more stable than reactant.
  3. Activation energy of backward reaction is E1 and product is more stable than reactant.
  4. Activation energy of forward reaction is E1 + E2 and product is less stable than reactant.

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