For the thermal decomposition of N2O5(g) at constant volume, the following table can be formed, for the reaction mentioned below. 2N2O5(g) 2N2O4(g)+O2(g) [figure] x= 10-3 atm [nearest integer] Given : Rate constant for the reaction is 4.606 10-2 s-1.
Answer
897
Solution
Concept: first order: kt= P0Pt, Pt = pressure of N2O5 left.
kt=4.606 10-2 100=4.606= 100 ⇒ 0.6-2p=0.006 ⇒ p=0.297 atm
2N2O5 2N2O4 + O2: Ptotal=(0.6-2p)+2p+p=0.6+p
∴ Ptotal=0.897 atm=897 10-3 atm
Answer: 897