50 mL of each gas A and of gas B takes 150 and 200 seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be
- 96
- 128.74
- 20.25
- 64.42
Answer
(3) 20.25
Solution
By Graham's law, for equal volumes effused, r 1t and r 1 M
tAtB = MAMB
150200 = MA36
MA36 = 916
MA = 9 3616 = 20.25
Answer: (3)