The potential for the given half cell at 298 K is (-) 10-2 V 2H+(aq) + 2e- H2(g) [H+] = 1 M, PH2 = 2 atm (Given : 2.303 RT/F = 0.06 V, 2 = 0.3)
Answer
1
Solution
Nernst equation (n = 2), E H+/H2 = 0:
E = E - 0.062 PH2[H+]2
⇒ E = 0 - 0.03 212
⇒ E = -0.03 0.3 = -0.009 V
∴ E = -0.9 10-2 V ≈ -1 10-2 V (nearest integer)
Answer: 1