The amount of electricity in Coulomb required for the oxidation of 1 mol of H2O to O2 is 105 C.
Answer
2
Solution
Oxidation at the anode: 2H2O O2 + 4H+ + 4e-
⇒ 2 mol H2O need 4 mol e- ⇒ 1 mol H2O needs 2 mol e- = 2 F
∴ Q = 2 × 96500 = 1.93 × 105 C ≈ 2 × 105 C
Answer: 2