The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is :
- 600
- 300
- 900
- 150
Answer
(4) 150
Solution
1 = 600 rpm = 60060 = 10 rev/s; 2 = 1200 rpm = 20 rev/s
For uniform angular acceleration, number of revolutions = average rate × time
N = 1 + 22 t = 10 + 202 10
= 150 revolutions
Answer: (4)