The radius of gyration of a solid sphere of mass 5 kg about XY is 5 m as shown in figure. The radius of the sphere is 5x 7 m, then the value of x is: [figure]
- 5
- 2
- 3
- 5
Answer
(4) 5
Solution
XY is a tangent to the sphere. By the parallel axis theorem:
IXY = 25MR2 + MR2 = 75MR2
MK2 = 75MR2 R2 = 5K27 = 5 257
R = 5 5 7 m
Comparing with 5x 7: x = 5
Answer: (4)