A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is: [figure]
- 757
- 764
- 78
- 740
Answer
(1) 757
Solution
Let the mass of the complete sphere (radius 2R) be M. Mass volume, so the small sphere has mass M8.
Complete sphere about the Y-axis (a diameter): I0 = 25M(2R)2 = 85MR2
Small sphere (centre at distance R from the Y-axis), parallel-axis theorem:
I1 = 25 ( M8 )R2 + M8R2 = 740MR2
Remaining part: I2 = I0 - I1 = 6440MR2 - 740MR2 = 5740MR2
I1I2 = 757
Answer: (1)