The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm2. The length of the 400 g rod is nearly:
- 8.5 cm
- 17.5 cm
- 20.7 cm
- 72.0 cm
Answer
(1) 8.5 cm
Solution
I = ML212
2400 = 400 L212
L2 = 72 cm2
L = 72 8.5 cm
Answer: (1)