The equations of two sides AB and AC of a triangle ABC are 4x + y = 14 and 3x - 2y = 5, respectively. The point (2, - 43 ) divides the third side BC internally in the ratio 2 : 1, the equation of the side BC is
- x + 6y + 6 = 0
- x - 3y - 6 = 0
- x + 3y + 2 = 0
- x - 6y - 10 = 0
Answer
(3) x + 3y + 2 = 0
Solution
B on AB: B(p, 14 - 4p); C on AC: C (q, 3q - 52 )
D divides BC in 2 : 1: 2q + p3 = 2, (3q - 5) + (14 - 4p)3 = - 43
p + 2q = 6, 4p - 3q = 13 p = 4, q = 1
B(4, -2), C(1, -1)
[figure]
Slope of BC = -1 + 21 - 4 = - 13 y + 1 = - 13(x - 1)
x + 3y + 2 = 0
Answer: (3)