From the circuit given below, the capacitance between terminals A and B shown in the circuit is μF. (take C1=C2=C3=1 μF and C4=2 μF.) [figure]
- 2
- 7/2
- 7/3
- 5/2
Answer
(1) 2
Solution
Let P be the junction of C1 and C2. The upper wire joins point A to the junction of C2 and C3, so that junction is also point A.
C1: A to P, C2: P to A C1 C2 between A and P
C4: P to B; C3: A to B
[figure]
C12=C1+C2=1+1=2 μF
C12 in series with C4: 2 22+2=1 μF
In parallel with C3: CAB=1+1=2 μF
Answer: (1)