In the circuit shown in the figure, the input voltage Vi is 20 V, VBE = 0 and VCE = 0. The values of IB, IC and β are given by [figure]
- IB = 40 , IC = 10 mA, β = 250
- IB = 25 , IC = 5 mA, β = 200
- IB = 20 , IC = 5 mA, β = 250
- IB = 40 , IC = 5 mA, β = 125
Answer
(4) IB = 40 , IC = 5 mA, β = 125
Solution
Base circuit: Vi = IB RB + VBE
⇒ IB = 20 - 0500 103 A = 4 10-5 A = 40
Collector circuit: VCC = IC RC + VCE
⇒ IC = 20 - 04 103 A = 5 10-3 A = 5 mA
∴ = ICIB = 5 10-340 10-6 = 125
Answer: (4)