Let a = 6 i + j - k and b = i + j. If c is a vector such that | c| 6, a c = 6| c|, | c - a| = 2 2 and the angle between a b and c is 60 , then |( a b) c| is equal to:
- 32 6
- 92(6 - 6)
- 92(6 + 6)
- 32 3
Answer
(3) 92(6 + 6)
Solution
a b = vmatrix i & j & k \ 6 & 1 & -1 \ 1 & 1 & 0 vmatrix = i - j + 5 k ⇒ | a b| = 27 = 3 3
| c - a|2 = 8 | c|2 + | a|2 - 2 a c = 8
| c|2 + 38 - 12| c| = 8 | c|2 - 12| c| + 30 = 0
| c| = 6 6; ∵ | c| 6 ⇒ | c| = 6 + 6
|( a b) c| = | a b| | c| 60
= 3 3(6 + 6) 32 = 92(6 + 6)
Answer: (3)