If A(1, -1, 2), B(5, 7, -6), C(3, 4, -10) and D(-1, -4, -2) are the vertices of a quadrilateral ABCD, then its area is :
- 24 7
- 48 7
- 24 29
- 12 29
Answer
(4) 12 29
Solution
[figure]
Area of a quadrilateral = 12| AC BD|, where AC and BD are its diagonals.
AC = 2 i + 5 j - 12 k, BD = -6 i - 11 j + 4 k
AC BD = vmatrix i & j & k \ 2 & 5 & -12 \ -6 & -11 & 4 vmatrix = -112 i + 64 j + 8 k = 8(-14 i + 8 j + k)
Area = 12 8 196 + 64 + 1 = 4 261 = 12 29
Answer: (4)