In a system two particles of masses m1 = 3 kg and m2 = 2 kg are placed at certain distance from each other. The particle of mass m1 is moved towards the center of mass of the system through a distance 2 cm. In order to keep the center of mass of the system at the original position, the particle of mass m2 should move towards the center of mass by the distance cm.
Answer
3
Solution
xcm = m1 x1 + m2 x2m1 + m2 = 0
both move towards the CM (opposite directions): m1 d1 = m2 d2
3 2 = 2 d2
d2 = 3 cm
Answer: 3