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A body of mass 'm' is projected with a speed 'u' making an angle of 45 with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as 2mu3Xg. The value of 'X' is .
8
At the highest point velocity is horizontal, u 45 , at height H above O.
L=m(u 45 )H, where H= u2 2 45 2g= u24g
L=m u 2 u24g= mu34 2g= 2mu38g
X=8
Answer: 8
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