If M0 is the mass of isotope 125B, Mp and Mn are the masses of proton and neutron, then nuclear binding energy of isotope is:
- (5Mp + 7Mn - M0)C2
- (M0 - 5Mp - 7Mn)C2
- (M0 - 5Mp)C2
- (M0 - 12Mn)C2
Answer
(1) (5Mp + 7Mn - M0)C2
Solution
125B: protons = 5, neutrons = 12 - 5 = 7
Mass defect m = (5Mp + 7Mn) - M0 (positive: nucleus is lighter than its free nucleons)
binding energy = m c2
B.E. = (5Mp + 7Mn - M0)C2
(2): the negative of the binding energy, so (2) is wrong.
(3): the 7 neutrons are left out, so (3) is wrong.
(4): the 5 protons are left out, so (4) is wrong.
Answer: (1)