An inductor stores 16 J of magnetic field energy and dissipates 32 W of thermal energy due to its resistance when an a.c. current of 2 A (rms) and frequency 50 Hz flows through it. The ratio of inductive reactance to its resistance is . ( = 3.14)
Answer
314
Solution
Magnetic energy: U = 12LI2 16 = 12L(2)2 L = 8 H
Heat dissipated: P = Irms2 R 32 = (2)2 R R = 8
Inductive reactance: XL = 2 fL = 2 3.14 50 8 = 2512
XLR = 25128 = 314
Answer: 314