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Thermodynamics (Physics) · Question 5

JEE Main 2026 (Online) 5th April Morning ShiftMCQMedium📈 Topic in 3% papers+4−1
1

Consider the following statements: Choose the correct combination of statements from the options given below:

  1. C, D and E Only
  2. A, B and C Only
  3. A, B and D Only
  4. B, C and D Only

Answer

(3) A, B and D Only

Solution

A. The zeroth law (thermal equilibrium) leads to the concept of temperature ⇒ correct.

B. The first law Q= U+ W introduces internal energy as a state function ⇒ correct.

C. Isothermal process of an ideal gas: T=0 ⇒ U=0 ⇒ Q= W ⇒ the statement Q W is incorrect.

D. Intensive × extensive is extensive, e.g. density × volume = mass, pressure × volume ∝ energy ⇒ correct.

E. Extensive variable ÷ mass is a specific quantity, e.g. Vm (specific volume), which does not depend on the amount of matter ⇒ intensive ⇒ incorrect.

∴ Correct statements: A, B and D.

Answer: (3)

JEE Main 2026 (Online) 5th April Morning Shift

Keep practising — Thermodynamics (Physics)

2

An ideal gas undergoes a process maintaining relation between pressure (P) and volume (V) as P=P0 (1+ ( V0V )2 )-1, where P0 and V0 are constants. If two samples A and B (two moles each) with initial volumes V0 and 3V0 respectively undergo above mentioned process and attain same pressure, then the difference in the temperatures of these samples, TB-TA is . (R = gas constant)

  1. 9P0V08R
  2. 11P0V010R
  3. 7P0V06R
  4. 13P0V011R
JEE Main 2026 (Online) 4th April Morning Shift
3

Heat is supplied to a diatomic gas at constant pressure. Then the ratio of Q : U : W is .

  1. 2 : 3 : 5
  2. 5 : 3 : 2
  3. 2 : 5 : 7
  4. 7 : 5 : 2
JEE Main 2026 (Online) 2nd April Morning Shift
4

A vessel contains 0.15 m3 of a gas at pressure 8 bar and temperature 140 °C with cp=3R and cv=2R. It is expanded adiabatically till pressure falls to 1 bar. The work done during this process is kJ. (R is gas constant)

JEE Main 2026 (Online) 2nd April Morning Shift
5

5 moles of unknown gas is heated at constant volume from 10 °C to 20 °C. The molar specific heat of this gas at constant pressure cp = 8 cal/mol.°C and R = 8.36 J/mol.°C. The change in the internal energy of the gas is calorie.

JEE Main 2026 (Online) 2nd April Evening Shift
6

In the following p - V diagram the equation of state along the curved path is given by (V - 2)2 = 4ap where a is a constant. The total work done in the closed path is [figure]

  1. + 13a
  2. - 1a
  3. 12a
  4. - 13a
JEE Main 2026 (Online) 28th January Morning Shift
7

A thermodynamic system is taken through the cyclic process ABC as shown in the figure. The total work done by the system during the cycle ABC is J. [figure]

JEE Main 2026 (Online) 28th January Evening Shift
8

Densities of water at 4 and 20 are 1000 kg/m3 and 998 kg/m3 respectively. The increase in internal energy of 4 kg of water when it is heated from 4 to 20 is J. (specific heat capacity of water = 4.2 kJ/kg K and 1 atmospheric pressure = 105 Pa)

  1. 268799.2
  2. 315826.2
  3. 234699.2
  4. 258700.8
JEE Main 2026 (Online) 24th January Morning Shift
9

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1 to P2 is Joule (P1 = 21.7 Pa and P2 = 30 Pa, Cv = 21 J/K mol, R = 8.3 J/mol K). The value of is . [figure]

  1. 21
  2. 28
  3. 24
  4. 15
JEE Main 2026 (Online) 24th January Evening Shift
10

When 300 J of heat is given to an ideal gas with Cp = 72R, its temperature rises from 20 to 50 keeping its volume constant. The amount of the gas is (approximately) 10-3 mol. (R = 8.314 J/mol K)

JEE Main 2026 (Online) 24th January Evening Shift
11

One mole of an ideal diatomic gas expands from volume V to 2V isothermally at a temperature 27 and does W joule of work. If the gas undergoes same magnitude of expansion adiabatically from 27 doing the same amount of work W, then its final temperature will be (close to) . ( e 2 = 0.693)

  1. -56
  2. -117
  3. -30
  4. -189
JEE Main 2026 (Online) 23rd January Evening Shift

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