In series LCR circuit, the capacitance is changed from C to 4C. To keep the resonance frequency unchanged, the new inductance should be:
- increased by 2 L
- reduced by 14 L
- reduced by 34 L
- increased to 4 L
Answer
(3) reduced by 34 L
Solution
f0 = 12 LC unchanged L'C' = LC
L'(4C) = LC L' = L4
decrease = L - L4 = 34L
Answer: (3)