A particle initially at rest starts moving from reference point x=0 along x-axis, with velocity v that varies as v=4 x m/s. The acceleration of the particle is ms-2.
Answer
8
Solution
a=v dvdx ( v is given in terms of x)
v=4 x dvdx= 2 x
a=4 x 2 x=8 m s-2 (constant)
Answer: 8