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The relation between time 't' and distance 'x' is t= x2+ x, where and are constants. The relation between acceleration (a) and velocity (v) is :
(3) a=-2 v3
t= x2+ x; differentiate w.r.t. x:
dtdx=2 x+ v= 12 x+
a= dvdt=- 2 (2 x+ )2 dxdt
=-2 v2 v
a=-2 v3
Answer: (3)
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