A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
- MV
- 1.5 MV
- 2MV
- zero
Answer
(3) 2MV
Solution
Impulse = change in momentum
Initial momentum = +MV, final momentum = -MV (reversed direction)
J = (-MV) - (+MV) = -2MV
Magnitude of impulse = 2MV
Answer: (3)