Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be :
- Mv2 newton
- zero
- Mv newton
- 2 Mv newton
Answer
(3) Mv newton
Solution
Force = rate of change of momentum, F = d(mv)dt
The velocity v is constant, so F = v dmdt
Here dmdt = M kg/s
F = Mv newton
Answer: (3)